Материалы по запросу: y4 cos2x

y = e + 1   ex – y · y` = 1 y(0) = 0 y(1)   3 dy + y sinx dx = 0 y(π/2) = 1 y(π)   y4 cosx + 3y` = 0 y(0) = 1 y(π)   y` + 3y tg3x = 0 y(0) = 1 9y2 + y`2   x dy = (x + y) dx