Ответ на вопрос
To find the values of a and b, we can expand the right side of the equation and compare it to the given equation.(x+a)(x+b) = x^2 + (a+b)x + abNow, we know that the equation x^2 - 13x + 42 is equivalent to the expanded form x^2 + (a+b)x + ab. By comparing the coefficients of x and the constant term on both sides, we can determine the values of a and b.From the equation x^2 - 13x + 42 = x^2 + (a+b)x + ab, we can see that:
a + b = -13
ab = 42Now, we need to find two numbers that multiply to 42 and add up to -13. These two numbers are -6 and -7.Therefore, a = -6 and b = -7. So, x^2 - 13x + 42 = (x-6)(x-7).
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